## Unique distinct values from multiple columns using array formula

**Question:** I have cell values spanning over several columns and I want to create a unique list from that range. How?

**Answer:**

*Thanks to Eero, who contributed the original array formula!*

**Unique distinct text values from range tbl_text, array formula in B13:**

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### How to enter an array formula

- Double click on cell B13
- Copy and paste above formula to cell B13
- Press and hold CTRL + SHIFT simultaneously
- Press Enter once
- Release all keys

Your formula now looks like this: {=array_formula}

Don't enter these characters yourself, they appear automatically when you do above steps.

Recommended article

Learn the basics of Excel arrays

Array formulas allows you to do advanced calculations not possible with regular formulas.

### How to copy array formula

Copy cell B13 and paste it down as far as necessary.

**Unique distinct numbers from range tbl_num, array formula in D13:**

Copy cell D13 and paste it down as far as necessary.

### Explaining array formula in cell B13

The array formula has two parts. One part returns row numbers and the other part returns column numbers. Let us begin with the first part, returning row numbers.

**Step 1 - Find new unique distinct text values**

=INDEX(tbl_text, MIN(IF(**COUNTIF($B$12:B12, tbl_text)=0**, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), MATCH(0, COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1)), 0), 1)

COUNTIF(range,criteria) - Counts the number of cells within a range that meet the given condition

COUNTIF($B$12:B12, tbl_text)=0

becomes

COUNTIF("Text", {"Apple","Banana","Lemon";"Orange","Lemon","Apple";"Lemon","Banana","Orange"})=0

becomes

{0,0,0;0,0,0;0,0,0}=0

becomes

{TRUE,TRUE,TRUE;TRUE,TRUE,TRUE;TRUE,TRUE,TRUE}

Learn to use the COUNTIF function

Counts the number of times a value exists in a cell range.

**Step 2 - Convert boolean array to row numbers**

=INDEX(tbl_text, MIN(I**F(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)**), MATCH(0, COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1)), 0), 1)

IF(logical_test,[value_if:true],[value_if_false]) checks whether a condition is met, and returns one value if TRUE, and another value if FALSE

IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)

becomes

IF({TRUE,TRUE,TRUE;TRUE,TRUE,TRUE;TRUE,TRUE,TRUE}, {2;3;4}-MIN({2;3;4})+1)

becomes

IF({TRUE,TRUE,TRUE;TRUE,TRUE,TRUE;TRUE,TRUE,TRUE}, {2;3;4}-MIN({2;3;4})+1)

becomes

IF({TRUE,TRUE,TRUE;TRUE,TRUE,TRUE;TRUE,TRUE,TRUE}, {2;3;4}-2+1)

becomes

IF({TRUE,TRUE,TRUE;TRUE,TRUE,TRUE;TRUE,TRUE,TRUE}, {1;2;3}) and returns {1,1,1;2,2,2;3,3,3}

Check if a logical expression is met. Returns a specific value if TRUE and another specific value if FALSE.

**Step 3 - Extract smallest value in array**

=INDEX(tbl_text, **MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1))**, MATCH(0, COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1)), 0), 1)

MIN(number1,[number2])

Returns the smallest number in a set of values. Ignores logical values and text

MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1))

becomes

MIN({1,1,1;2,2,2;3,3,3}) and returns 1.

**Step 4 - Part two, identify array values in current row**

=INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), MATCH(0, COUNTIF($B$12:B12, **INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1)**), 0), 1)

INDEX(array,row_num,[column_num]) returns a value or reference of the cell at the intersection of a particular row and column, in a given range

INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1))

becomes

INDEX(tbl_text, MIN({1,1,1;2,2,2;3,3,3}), , 1))

becomes

INDEX(tbl_text, 1, , 1)) returns array {"Apple", "Banana", "Lemon"}

Fetch a value in a data set based on coordinates.

**Step 5 - Find new unique distinct text values in current row**

=INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), MATCH(0, **COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1))**, 0), 1)

COUNTIF(range,criteria) counts the number of cells within a range that meet the given condition

COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1))

becomes

COUNTIF("Text", {"Apple", "Banana", "Lemon"}) and returns {0,0,0}

**Step 6 - Find a new unique distinct text value in current row**

=INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), **MATCH(0, COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1)), 0)**, 1)

MATCH(lookup_value;lookup_array; [match_type]) returns the relative position of an item in an array that matches a specified value

MATCH(0, COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1)), 0)

becomes

MATCH(0, {0,0,0}, 0) returns 1.

How to use Excel’s MATCH function

Identify the position of a value in an array.

**Step 7 - **All together

=INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), MATCH(0, COUNTIF($B$12:B12, INDEX(tbl_text, MIN(IF(COUNTIF($B$12:B12, tbl_text)=0, ROW(tbl_text)-MIN(ROW(tbl_text))+1)), , 1)), 0), 1)

becomes

=INDEX(tbl_text, 1, 1) returns value "Apple" in cell B13.

### Explaining array formula in cell D13

=LARGE(IF(COUNTIF($D$12:D12, tbl_num)=0, tbl_num, ""), 1)

**Step 1 - Remove previously extracted values above current cell with an array with boolean values **

=LARGE(IF(**COUNTIF($D$12:D12, tbl_num)=0**, tbl_num, ""), 1)

COUNTIF(range,criteria) - Counts the number of cells within a range that meet the given condition

COUNTIF($D$12:D12, tbl_num)=0

becomes

{0,0,0;0,0,0;0,0,0}=0

becomes

{TRUE,TRUE,TRUE;TRUE,TRUE,TRUE;TRUE,TRUE,TRUE}

**Step 2 - Convert boolean values to numeric values**

=LARGE(**IF(COUNTIF($D$12:D12, tbl_num)=0, tbl_num, "")**, 1)

IF(logical_test;[value_if:true];[value_if_false]) checks whether a condition is met, and returns one value if TRUE, and another value if FALSE

IF(COUNTIF($D$12:D12, tbl_num)=0, tbl_num, "")

becomes

IF({TRUE,TRUE,TRUE;TRUE,TRUE,TRUE;TRUE,TRUE,TRUE}, {1, 2, 1;2, 4, 3;1, 3, 1}, "")

becomes

{1, 2, 1;2, 4, 3;1, 3, 1}

**Step 3 - Convert boolean values to numeric values**

LARGE(array,k) returns the k-th largest row number in this data set.

=LARGE(IF(COUNTIF($D$12:D12, tbl_num)=0, tbl_num, ""), 1)

becomes

=LARGE({1, 2, 1;2, 4, 3;1, 3, 1}, 1) returns 4 in cell D13.

SMALL function and LARGE function

This function lets you extract any number in a cell range based on sort rank.

### Download excel sample file for this article.

Unique-distinct-values-from-multiple-columns-using-array-formulas.xls

(Excel 97-2003 Workbook *.xls)

Create a unique distinct alphabetically sorted list extracted from a column

The formula in cell D3 extracts unique distinct values sorted A to Z, from column B to column D. Unique […]Extract a unique distinct list by matching items that meet a criterion

Anura asks: Is it possible to extend this by matching items that meet a criteria? I have a list of […]How to create a unique distinct list where other columns meet two criteria

Question: How do I create a unique distinct list where other columns meet two criteria using excel array formula? Answer: […]You can click on headers to sort table for easy finding.

### 23 Responses to “Unique distinct values from multiple columns using array formula”

### Leave a Reply

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**Contact Oscar**

You can contact me through this webpage

A slightly different approach to extract unique items from a N*M table (named as "tbl" in the formula).

So type say "Unique items from the table" in A1 and enter the following formula as an array into A2 and copy it down as far as necessary.(it is supposed column A to be free)

=INDEX(tbl,MIN(IF(COUNTIF($A$1:A1,tbl)=0,ROW(tbl)-MIN(ROW(tbl))

+1)),MATCH(0,COUNTIF($A$1:A1,INDEX(tbl,MIN(IF(COUNTIF($A$1:A1,tbl)=0,ROW(tbl)-MIN

(ROW(tbl))+1)),,1)),0),1)

Thank you! Your formula is working perfectly! No need for a "helper" column!

Hi,

How I can extend "tbl_text" as reported in your example??

I need to enlarge that range for a bigger table.

Thanks,

Fabio,

Use "Name Manager" to change range.

https://office.microsoft.com/en-us/excel-help/define-and-use-names-in-formulas-HA010147120.aspx

It works now!

Many thanks,

Fabio

If a blank cell is located anywhere in the tbl, the formula returns the blank. I guess technically a blank is a unique value in the tbl but I'm trying to make sure only relevant numbers are returned. Any thoughts on how to correct this?

Curious,

Download example file:

Unique-distinct-values-from-multiple-columns-using-array-formulas-without-blanks.xls

Hi Oscar,

at the end there is a #N/A in this file can you please suggest me how to get rid of it.

thanks for your help.

Sandeep,

=IFERROR(formula, "")

I have tried the formulas in this article and some from other articles and comments, but none have worked for my particular problem. I'd appreciate any help/insight.

I have several worksheets, each with a table inserted. I would like to create the list of uniques in the column of the summary worksheet's table. The methods on this site work for creating a list from a 1/2/3 columns, but fails for multiple columns (in my case). I have 4 and I'd rather understand the "general" approach than keep creating ever more convoluted formulas as columns increase.

I have created a named range that spans 4 worksheets (in the Name Manager - Name: MultiPC Refers To=A[PC],B[PC],C[PC],D[PC] -- references 4 table columns on separate worksheets).

The formulas create several errors. Stepping through them, when it tries to evaluate INDEX(*MultiPC*,... it says that it will result in an error. The value for MultiPC shown below the formula is the absolute references for MultiPC (comma separated between sheets, e.g. Sheet1!$B$2:$B$31,Sheet2!$B$2:$B:23...).

I'm guessing it's because the named range doesn't consitute an array (not rectangular? is this the case with all non-contiguous ranges?). I'm not really sure if that's the problem and how to tackle it. I've thought about making hidden columns in a single worksheet for the unique list of each worksheet, then applying this approach. Another alternative might be to extend the 3-column method from here https://www.get-digital-help.com/2009/06/20/extract-a-unique-distinct-list-from-three-columns-in-excel/ (add another nested IFERROR(INDEX...MATCH(...COUNTIF(... ), but again, I'm trying to learn a general solution that doesn't require an ever-expanding formula.

Of course, it'd be a cinch if I was allowed to use VBA for this project, but our workplace doesn't allow macros, so I'm stuck using formulas at the moment. What's your opinion? Thanks a lot!

So, I almost have it set. Using either of your array formulas below for refering to a 4-column list, I'm having trouble with a "0" (zero) being placed when blank cells are in the referenced columns. Any ideas of how to eliminate this zero? If I reference 3 columns only, there's no problem. by the way, thanks so much for the info on your website.

=IFERROR(IFERROR(IFERROR(IFERROR(INDEX(List1, MATCH(0, COUNTIF($E$1:E1, List1), 0)), INDEX(List2, MATCH(0, COUNTIF($E$1:E1, List2), 0))), INDEX(List3, MATCH(0, COUNTIF($E$1:E1, List3), 0))), INDEX(List4, MATCH(0, COUNTIF($E$1:E1, List4), 0))), "")

=IFERROR(INDEX($B$15:$D$64, MIN(IF((COUNTIF($F$14:$F14, $B$15:$D$64)=0)*($B$15:$D$64""), ROW($B$15:$D$64)-MIN(ROW($B$15:$D$64))+1)), MATCH(0, COUNTIF($F$14:$F14, INDEX($B$15:$D$64, MIN(IF((COUNTIF($F$14:$F14, $B$15:$D$64)=0)*($B$15:$D$64""), ROW($B$15:$D$64)-MIN(ROW($B$15:$D$64))+1)), , 1)), 0), 1),"")

Colin,

See this workbook:

https://www.get-digital-help.com/wp-content/uploads/2014/10/Unique-distinct-values-from-four-ranges-with-blanks.xlsx

Named ranges

List1:=Sheet1!$A$1:$A$7

List2:=Sheet1!$C$1:$C$7

List3:=Sheet1!$E$1:$E$7

List4:=Sheet1!$G$1:$G$8

Zeta,

I have several worksheets, each with a table inserted. I would like to create the list of uniques in the column of the summary worksheet's table. The methods on this site work for creating a list from a 1/2/3 columns, but fails for multiple columns (in my case). I have 4 and I'd rather understand the "general" approach than keep creating ever more convoluted formulas as columns increase.Here is an example of four columns:

how-to-extract-a-unique-list-from-four-columns-in-excel.xlsx

I'm guessing it's because the named range doesn't consitute an array (not rectangular? is this the case with all non-contiguous ranges?). I'm not really sure if that's the problem and how to tackle it. I've thought about making hidden columns in a single worksheet for the unique list of each worksheet, then applying this approach. Another alternative might be to extend the 3-column method from here https://www.get-digital-help.com/2009/06/20/extract-a-unique-distinct-list-from-three-columns-in-excel/ (add another nested IFERROR(INDEX...MATCH(...COUNTIF(... ), but again, I'm trying to learn a general solution that doesn't require an ever-expanding formula.I am sorry, I don´t have a general solution to this problem.

Oscar,

I really appreciate your reply. Your site is an incredible resource. I used the 4-column formula you provided, but if I find a method that works for N columns across multiple sheets, I will let the folks here know!

Thanks again,

Z

Thank you for writing this, it works like a charm!

However, there is one thing I would like to do different:

When I enter more entries in the array, the list updates with new entries in the order of first looking through the row, then going down the column. I would prefer the list first list the unique values in the column going downward, then then next column downward etc. Is that possible?

Thank you

Jonas,

See this file:

Unique-distinct-values-from-multiple-columns-using-array-formulas-jonas.xls

[...] The answer is that there is no need for multiple duplicate columns in the array. Excel simplifies the array down to a single column. But when used with multiple cell ranges in more complicated array formulas, make sure the number of rows match. See this example: Unique distinct values from a cell range [...]

[…] As the name also implies, the data in G2:J14 is expected to be text with length > 0. Source. Unique distinct values from multiple columns using array formula | Get Digital Help - Microsoft Exce… The basic MATCH/COUNTIF has been attributed to Eero (a contributor at the now defunct MS […]

I realize this is an old thread but its the closest I have been able to get to a solution for my problem. I am working with a data set spread across multiple sheets. I am pulling unique distinct a-z sorted values from a column with a single criteria. I am using a helper column on my "summary" sheet for each of the sheets I pull data from. I am then combining this into a unique distinct sorted list without blanks. The "summary" page is getting quite processor intensive with all the helper columns I am using. Is there a way to add a single criteria element to the formula? Basically a Unique distinct sorted list from two columns with a single criteria removing blanks?

I am interested in counting unique values across 8 columns in Excel that are not adjoining (i.e. AF, AN, AV, BD, BL, BT, CB, CJ). I have found functions to count in one or two columns but nothing for 8 and I cannot adapt them for my issue. Any suggestions?

Very helpful article - many thanks for posting the formula and the explanation. It did exactly as specified on the tin.

Great Formula! Thank You for posting and keeping it here.

Hi,

I have more than 20 columns with true and false values. How do i get the names of top ten column with true values?