Filter unique distinct records with a condition
If Tea and Coffee has Americano,it will only return Americano once and not twice. I am looking for a unique distinct list based on each condition.
I remember reading that Excel has difficulty with these type of or conditions in arrays.
Answer:
Array formula in cell C19:
To enter an array formula, type the formula in a cell then press and hold CTRL + SHIFT simultaneously, now press Enter once. Release all keys.
The formula bar now shows the formula with a beginning and ending curly bracket telling you that you entered the formula successfully. Don't enter the curly brackets yourself.
Copy array formula
- Select cell C19
- Copy cell (Ctrl + c)
- Select cell range C19:D22
- Paste (Ctrl + v)
How the array formula in cell C19 works
Step 1 - Identify unique distinct records
COUNTIFS($C$18:C18, $C$5:$C$11, $D$18:D18, $D$5:$D$11)
becomes
COUNTIFS("Category", {"Coffee";"Coffee";"Coffee";"Coffee";"tea";"juice";"tea"}, "Item", {"Espresso";"Espresso";"Americano";"Americano";"Americano";"Florida";"English"},)
and returns {0;0;0;0;0;0;0}
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Checks multiple conditions against the same number of cell ranges and counts how many times all criteria are met.
Step 2 - Filter records with condition
COUNTIF($C$13:$C$14, $C$5:$C$11)=0
becomes
COUNTIF({"Coffee"; "tea"}, {"Coffee"; "Coffee"; "Coffee"; "Coffee"; "tea"; "juice"; "tea"})=0
and returns {FALSE; FALSE; FALSE; FALSE; FALSE; TRUE; FALSE}
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Counts the number of cells that meet a specific condition.
Step 3 - Match filtered records
MATCH(0, COUNTIFS($C$18:C18, $C$5:$C$11, $D$18:D18, $D$5:$D$11)+(COUNTIF($C$13:$C$14, $C$5:$C$11)=0), 0)
becomes
MATCH(0, {0;0;0;0;0;0;0}+{FALSE; FALSE; FALSE; FALSE; FALSE; TRUE; FALSE}, 0)
becomes
MATCH(0, {0;0;0;0;0;1;0},0)
and returns 1.
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Identify the position of a value in an array.
Step 4 - Return a value or reference of the cell at the intersection of a particular row and column
INDEX($C$5:$D$11, MATCH(0, COUNTIFS($C$18:C18, $C$5:$C$11, $D$18:D18, $D$5:$D$11)+(COUNTIF($C$13:$C$14, $C$5:$C$11)=0), 0), COLUMN(A1))
becomes
INDEX({"Coffee", "Espresso";"Coffee", "Espresso";"Coffee", "Americano";"Coffee", "Americano";"tea", "Americano";"juice", "Florida";"tea", "English"}, 1, 1)
and returns "Coffee" in cell C19.
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Gets a value in a specific cell range based on a row and column number.
Tip! Did you know that a pivot table can easily extract unique distinct records too?
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A pivot table allows you to examine data more efficiently, it can summarize large amounts of data very quickly and is very easy to use.
How to remove errors
IFERROR(value, value_if_error) returns value_if_error if expression is an error and the value of the expression itself otherwise
The array formula becomes:
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Oscar, this works great. Keep up the great work.
When I tried the workbook that was uploaded to this post-reply and pressed with left mouse button on the formula bar for cell C19 and hit 'ENTER' (without actually changing anything) and I get an #N/A record.
I'm running excel 2010, so I can only assume that the code in cell C19 'may' not work in 2010? Could this be possible? If so, can you help me with code that would work in Excel 2010??
Carlos,
When I tried the workbook that was uploaded to this post-reply and pressed with left mouse button on the formula bar for cell C19 and hit 'ENTER' (without actually changing anything) and I get an #N/A record.
That is one of the disadvantages with array formulas. If you edit an array formula (even though you don´t do any changes) you must enter it as an array formula. See: How to create an array formula, above.
I'm running excel 2010, so I can only assume that the code in cell C19 'may' not work in 2010? Could this be possible? If so, can you help me with code that would work in Excel 2010??
It works in excel 2010.