# Count overlapping days in multiple date ranges, part 2

In the previous post I explained how to count overlapping dates comparing a single date range against multiple date ranges. In this article, I will demonstrate how to count overlapping dates across multiple date ranges.

The date ranges are in columns A and B. The calendar to the right is there so that you can easily verify that the formula is correct.

#### What's on this webpage

## 1. Count the number of overlapping date ranges for each date

The first formula returns an array that counts the number of overlapping date ranges for each date. It is shown in cell range D12:Q12.

The formula returns this array:Â {1, 2, 1, 3, 1, 2, 2, 1, 0, 1, 1, 4, 3, 1}

Date 2005-01-01 is overlapped once by date range 2005-01-01/2005-01-02. So the first value in the array is 1.

Date 2005-01-02 is overlapped twice by date rangeÂ 2005-01-01/2005-01-02 and 2005-01-02/2005-01-04. The second value in the array is 2.

...

Date 2005-01-09 is not overlapped at all so the ninth value in the array is 0 (zero).

And so on.., you can verify these numbers against the calendar above.

## 2. Count dates overlapped by two or more date ranges

The second array formula returns an array that indicates if a date is overlapped by two or more date ranges. It is entered in cell range E14:R14.

This formula returnsÂ {0, 1, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0}

If we sum this array we get the total number of overlapped dates. That value is shown cell D15 and R13.

### 2.1 Explaining formula in cell range D13:Q13

#### Step 1 - Find latest date in end dates

The MAX function returns the largest number from a cell range or array.

MAX($C$3:$C$12)

becomes

MAX({38356; 38360; 38358; 38365; 38366; 38354; 38365; 38356; 38359; 38364})

and returns 38366. Note that these numbers are actually Excel dates, numbers formatted as dates. 38366 is 1/14/2005.

#### Step 2 - Find earliest date in start dates

The MIN function returns the largest number from a cell range or array.

MIN($B$3:$B$12)

becomes

MIN({38354; 38359; 38356; 38362; 38364; 38353; 38364; 38356; 38358; 38364})

and returns 38353.

#### Step 3 - Subtract dates

MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))+1

becomes

38366 - 38353 +1Â equals 14.

#### Step 4 - Create a cell reference

TheÂ INDEX functionÂ is also able to create a cell reference.

INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1)

becomes

INDEX($A:$A, 14)

and returns cell reference A14.

#### Step 5- Concatenate cell references

You need to use the ampersand character & to concatenate strings, however, not necessary in this rare case.

A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1)

returns cell reference A1:A14.

#### Step 6 - Calculate row numbers based on a cell reference

TheÂ ROW functionÂ returns a row number from a cell reference. It returns multiple row numbers if the cell reference points to a cell range.

ROW(A1:INDEX($A:$A, MAX($B$2:$B$11)-MIN($A$2:$A$11)+1))

becomes

ROW( A1:A14)

and returns {1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13; 14}.

#### Step 5 - Subtract array with 1

ROW(A1:INDEX($A:$A, MAX($B$2:$B$11)-MIN($A$2:$A$11)+1))-1

becomes

{1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13; 14}-1

and returns

{0; 1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13;}

#### Step 6 - Add array to earliest start date

MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1

becomes

38353+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1

becomes

38353 + {0; 1; 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12; 13;}

and returns

{38353; 38354; 38355; 38356; 38357; 38358; 38359; 38360; 38361; 38362; 38363; 38364; 38365; 38366}

#### Step 7 - Convert vertical array to a horizontal array

TheÂ TRANSPOSE functionÂ allows you to convert a vertical range to a horizontal range, or vice versa.

TRANSPOSE(array)

TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1)

becomes

TRANSPOSE({38353; 38354; 38355; 38356; 38357; 38358; 38359; 38360; 38361; 38362; 38363; 38364; 38365; 38366})

and returns

{38353, 38354, 38355, 38356, 38357, 38358, 38359, 38360, 38361, 38362, 38363, 38364, 38365, 38366}

#### Step 8 - Test which dates are larger or equal to start dates

TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1)>=$B$3:$B$12

becomes

{38353, 38354, 38355, 38356, 38357, 38358, 38359, 38360, 38361, 38362, 38363, 38364, 38365, 38366}>={38354; 38359; 38356; 38362; 38364; 38353; 38364; 38356; 38358; 38364}

and returns

{FALSE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, TRUE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE;FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, TRUE}

#### Step 9 - Test which dates are smaller or equal to end dates

TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1))<=$C$3:$C$12

returns

{TRUE, TRUE, TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, FALSE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE;TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, FALSE;TRUE, TRUE, TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE, FALSE;TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, TRUE, FALSE, FALSE}

#### Step 10 - Multiply arrays

(TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1)>=$B$3:$B$12)*((TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1))<=$C$3:$C$12)

returns

{0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0;0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1;1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0;0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0}

#### Step 11 - Create an array of numbers all equal to 1

Exponentiation is a mathematical operation, use the ^ character or theÂ POWER functionÂ to calculate the result of exponentiation.

TRANSPOSE($B$3:$B$12^0)

becomes

TRANSPOSE({38354; 38359; 38356; 38362; 38364; 38353; 38364; 38356; 38358; 38364}^0)

becomes

TRANSPOSE({1; 1; 1; 1; 1; 1; 1; 1; 1; 1})

and returns {1, 1, 1, 1, 1, 1, 1, 1, 1, 1}.

#### Step 12 - Evaluate MMULT function

TheÂ MMULT functionÂ calculatesÂ the matrix product of two arrays, an array as the same number of rows as array1 and columns as array2.

MMULT(TRANSPOSE($B$3:$B$12^0), (TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1)>=$B$3:$B$12)*((TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1))<=$C$3:$C$12))

becomes

MMULT({1, 1, 1, 1, 1, 1, 1, 1, 1, 1}, {0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0;0, 0, 0, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1;1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0;0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0;0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0})

and returns

{1, 2, 1, 3, 1, 2, 2, 1, 0, 1, 1, 4, 3, 1}

#### Step 13 - Check if value in array is larger than 1

MMULT(TRANSPOSE($B$3:$B$12^0), (TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1)>=$B$3:$B$12)*((TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1))<=$C$3:$C$12))>1

becomes

{1, 2, 1, 3, 1, 2, 2, 1, 0, 1, 1, 4, 3, 1}>1

and returns

{FALSE, TRUE, FALSE, TRUE, FALSE, TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, FALSE}

#### Step 14 - Convert boolean values

(MMULT(TRANSPOSE($B$3:$B$12^0), (TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1)>=$B$3:$B$12)*((TRANSPOSE(MIN($B$3:$B$12)+ROW(A1:INDEX($A:$A, MAX($C$3:$C$12)-MIN($B$3:$B$12)+1))-1))<=$C$3:$C$12))>1)*1

becomes

{FALSE, TRUE, FALSE, TRUE, FALSE, TRUE, TRUE, FALSE, FALSE, FALSE, FALSE, TRUE, TRUE, FALSE}*1

and returns

{0, 1, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0}.

Functions inÂ this post: MMULT, ROW, INDEX

Interested in learning more about excel formulas? Join my Advanced excel course.

### Count values category

This post demonstrates how to build formulas that counts unique distinct values based on criteria. The image above demonstrates an […]

This article describes how to count unique distinct values. What are unique distinct values?Â They are all values but duplicates are […]

This article explains how to count cells highlighted with Conditional Formatting (CF). The image above shows data in cell range […]

### Overlapping category

This article demonstrates formulas that show if a date range is overlapping another date range.Â The second section shows how […]

I found an old post that I think is interesting to write about today. Think of two overlapping ranges, it […]

The MEDIAN function lets you count overlapping dates between two date ranges. If you have more than two date ranges […]

### Excel categories

### 5 Responses to “Count overlapping days in multiple date ranges, part 2”

### Leave a Reply

### How to comment

**How to add a formula to your comment**

<code>Insert your formula here.</code>

**Convert less than and larger than signs**

Use html character entities instead of less than and larger than signs.

< becomes < and > becomes >

**How to add VBA code to your comment**

[vb 1="vbnet" language=","]

Put your VBA code here.

[/vb]

**How to add a picture to your comment:**

Upload picture to postimage.org or imgur

Paste image link to your comment.

**Contact Oscar**

You can contact me through this contact form

Hi Oscar,

Thanks for your knowledge sharing and really helpful!

You have mentioned the overlapping date within a single month. My question is how can we highlight the overlapping dates for 2 months. Kindly find the details below for your reference.

Date Format is in (MM/DD/YYYY)

Start - 03/28/2016 - End - 04/05/2016

Start - 04/25/2016 - End - 05/10/2016

I need your help in this issue. It will be great if I get the solution for this and the same will reduce my work upto 50%. Requesting you to provide me the solution for my query.

Regards

Sam Fredy. P

Hi Oscar,

Please help. Awaiting for your positive reply.

Regards

Sam

Hi Oscar,

Pls help me for my query.

Regards

Sam

My question is probably better suited here (I had initially posted in it Part 1). For this example, I want to find the maximum number of overlaps that occurred with a set of date ranges (i.e. in this example above, it would be four (or another way of looking at it is I want the Max value of Row 12).

This is so close to what I want. However, what I would LOVE to see in column "R" is the total number of days that one date overlaps all others.

For instance, the date range on row has 2 days that overlap 3 other date ranges. I would like to see the formula for calculating that 2 days in Column "R"

Then I can do a "Countifs" for the number days that overlap with other date ranges where the same "resource" has been assigned.

Is this possible?